Factors Affecting Capacitance in a Capacitor

In summary, the factors that increase capacitance of a capacitor include decreasing distance, increasing charge, and increasing area. The dielectric constant also plays a role, as increasing it will increase capacitance. The equation C = εA/d is a more accurate representation of the relationship between capacitance, charge, and electric field.
  • #1
Gear2d
51
0

Homework Statement



What will increase the capacitance of a capacitor?

Homework Equations



Q=CV
V = Ed

The Attempt at a Solution



Factors that increase:
-Decrease in distance
-Increase in charge
-Decrease in electric field
-Increase in area (length and width of the capacitor, but its thickness has no affect)

Would these be correct, also what about the dielectric constant (k), would increasing it increase capacitance or decrease it?
 
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  • #2


Gear2d said:

Homework Statement



What will increase the capacitance of a capacitor?

Homework Equations



Q=CV
V = Ed

The Attempt at a Solution



Factors that increase:
-Decrease in distance
-Increase in charge
-Decrease in electric field
-Increase in area (length and width of the capacitor, but its thickness has no affect)

Would these be correct, also what about the dielectric constant (k), would increasing it increase capacitance or decrease it?

Q = VC is not exactly the right equation to consider. The capacitor is the constant that relates the Charge to Voltage and is not a property of the capacitor per se. If you change the voltage then the charge changes as determined by the C - it is just descriptive of the relationship between Q and V as defined by C..

On the other hand:

C = εA/d would be more to the point of the question.

For more on capacitors read the link - https://www.physicsforums.com/library.php?do=view_item&itemid=112
 
  • #3


Hello Gear2d, I am Gear300...
Its pretty much what LowlyPion said. C = Q/V is somewhat deceptive. If you think about it, a stronger electric field should bring in more charges...and it does. If you decrease the value of E, then you decrease the value of Q. C is the constant, and what you would want is a more stable equation for it (provided by LowlyPion). If you want to further adjust the equation, then C = εA/d = Q/V = Q/(Ed)...Q = εAE...so charge increases with increasing electric field. Increasing the dielectric constant k increases the capacitance. If you want to know how, look for something correlating with a microscopic observation of capacitance and dielectrics.
 

1. What is the formula for capacitance?

The formula for capacitance is C = Q/V, where C represents capacitance in farads, Q is the charge stored on the capacitor in coulombs, and V is the potential difference across the capacitor in volts.

2. How do you calculate the capacitance of a parallel plate capacitor?

The capacitance of a parallel plate capacitor can be calculated using the formula C = ε0A/d, where ε0 is the permittivity of free space (8.85 x 10^-12 F/m), A is the area of the plates in square meters, and d is the distance between the plates in meters.

3. How does the distance between the plates affect the capacitance of a parallel plate capacitor?

The capacitance of a parallel plate capacitor is inversely proportional to the distance between the plates. This means that as the distance between the plates increases, the capacitance decreases, and vice versa.

4. What units is capacitance measured in?

Capacitance is measured in farads (F), which is equivalent to coulombs per volt (C/V).

5. How does the material between the plates affect the capacitance of a capacitor?

The material between the plates, also known as the dielectric material, affects the capacitance of a capacitor by changing the permittivity (ε) in the formula C = εA/d. Different materials have different permittivity values, which can increase or decrease the capacitance of a capacitor.

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