Another circuit task, but tricky.

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In summary: So just check that your sum is equal to 1.1V. Also, the yield of the voltaic element can be calculated by dividing the voltage drop across the external resistor (VR) by the total voltage (E), so yield = VR/E. In summary, the current in the circuit is 0.11A, the voltage drops across the external and internal portions are 0.99V and 0.11V respectively, and the yield of the voltaic element is 0.9.
  • #1
lymos
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Homework Statement


A voltaic element with electromotive voltage E=1,1V and with internal resistance r=1ohm, is connected to an external resistor with the resistance R=9ohm. Determine the current I which circulates in the circuit, also the falls of voltage on the external portion of the circuit VR and on the internal portion of the circuit Vr. Also, at what yield the voltaic element works?

Homework Equations


I=V/R

I=E/(r+R)

The Attempt at a Solution



The first step is easy, I mean calculating the I (I=E/(r+R)=1,1/(1+10)=0,11), but then I have some doubts.. Will it be right to calculate VR as VR=I*R and Vr as Vr=I*r? or maybe I must reduce something because it says: "the falls of voltage" so there should be a higher value and a smaller one.
 
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  • #2
lymos said:

Homework Statement


A voltaic element with electromotive voltage E=1,1V and with internal resistance r=1ohm, is connected to an external resistor with the resistance R=9ohm. Determine the current I which circulates in the circuit, also the falls of voltage on the external portion of the circuit VR and on the internal portion of the circuit Vr. Also, at what yield the voltaic element works?


Homework Equations


I=V/R

I=E/(r+R)

The Attempt at a Solution



The first step is easy, I mean calculating the I (I=E/(r+R)=1,1/(1+10)=0,11), but then I have some doubts.. Will it be right to calculate VR as VR=I*R and Vr as Vr=I*r? or maybe I must reduce something because it says: "the falls of voltage" so there should be a higher value and a smaller one.

It looks like you are doing it correctly. You calculated the current correctly, so now you get each individual voltage drop across each resistor by multiplying the current by each individual resistance. You can check your answers, because the sum of the voltage drops across the resistors must equal the value of the voltage source, correct?
 

Related to Another circuit task, but tricky.

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