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TFM
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[SOLVED] Distance between two charges where field strength = 0
Two particles having charges q1 = 0.500 nC and q2 = 9.00 nC are separated by a distance of 2.00 m.
At what point along the line connecting the two charges is the total electric field due to the two charges equal to zero?
[tex] E = \frac{1}{4 \pi \epsilon _0}\frac{q}{r^2} [/tex]
I have reduced this two:
[tex]\frac{q_1}{r_1^2} = \frac{q_2}{r_2^2}[/tex]
putting in the variables:
[tex]\frac{0.5*10^{-9}}{r_1^2} = \frac{9.0*10^{-9}}{r_2^2}[/tex]
I can rearrang to get:
[tex]\frac{r_2^2}{r_1_2} = \frac{9.0*10^{-9}}{0.5*10^{-9}}[/tex],
and:
[tex]\frac{r_2^2}{r_1_2} = 18 [/tex]
But I am not sure how to get the right distance to the actual point?
TFM
Homework Statement
Two particles having charges q1 = 0.500 nC and q2 = 9.00 nC are separated by a distance of 2.00 m.
At what point along the line connecting the two charges is the total electric field due to the two charges equal to zero?
Homework Equations
[tex] E = \frac{1}{4 \pi \epsilon _0}\frac{q}{r^2} [/tex]
I have reduced this two:
[tex]\frac{q_1}{r_1^2} = \frac{q_2}{r_2^2}[/tex]
The Attempt at a Solution
putting in the variables:
[tex]\frac{0.5*10^{-9}}{r_1^2} = \frac{9.0*10^{-9}}{r_2^2}[/tex]
I can rearrang to get:
[tex]\frac{r_2^2}{r_1_2} = \frac{9.0*10^{-9}}{0.5*10^{-9}}[/tex],
and:
[tex]\frac{r_2^2}{r_1_2} = 18 [/tex]
But I am not sure how to get the right distance to the actual point?
TFM