- #1
aisha
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Given [tex]\csc\theta = \frac {-17} {15} where \frac {3\pi} {2} < \theta <= 2\pi and \cot \beta = \frac {-3} {4} where \frac {\pi} {2} <= \beta <= \pi [/tex] Find the exact value of [tex] \cos (\theta-\beta)[/tex]
I think the theta angle is in quadrant 4, and the beta angle is in quadrant 2. I drew a circle with a cartesian plane and made the two right angle triangles beta and theta. The beta angle's opposite=4, adjacent=-3 and hypotenuse=5 (using pythagorean theorem) The theta angle's opposite= 15, adjacent = -17 and hypotenuse = square root of 514.
I'm not sure If I have done this correctly so far but this is all that I did and now I am stuck ... Please help! :uhh:
I think the theta angle is in quadrant 4, and the beta angle is in quadrant 2. I drew a circle with a cartesian plane and made the two right angle triangles beta and theta. The beta angle's opposite=4, adjacent=-3 and hypotenuse=5 (using pythagorean theorem) The theta angle's opposite= 15, adjacent = -17 and hypotenuse = square root of 514.
I'm not sure If I have done this correctly so far but this is all that I did and now I am stuck ... Please help! :uhh: