- #1
NewtonianAlch
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Homework Statement
Evaluating using CIF.
|z| = 4
Integral [itex]{\frac {{{\rm e}^{2\,iz}}{\it dz}}{ \left( 3\,z-1 \right) ^{2}}}[/itex]
The Attempt at a Solution
So the singularity here is z = 1/3 which is inside the circle.
Therefore using the formula [itex]2\,i\pi \,f[/itex] and substituting in the z = 1/3
We get f(1/3) = exp(2/3i)
So I get the answer of 2*Pi*i(exp(2/3i))
However the answer given is (-4Pi/9)(exp(2/3i))
I'm thinking it has something to do with the repeated root, but I'm not sure.