- #1
Pacopag
- 197
- 4
Homework Statement
We know that
[tex]\int_{-\infty}^\infty e^{-ax^2}dx = \sqrt{\pi \over a}[/tex].
Does this hold even if [tex]a[/tex] is complex?
Homework Equations
The Attempt at a Solution
In the derivation of the above equation, I don't see any reason why we must assume that [tex]a[/tex] be real. So I think it does hold for complex [tex]a[/tex].