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In a Griffith's book (page 15-16) an author derives a momentum operator. In the derivation he states that he used a integration by parts two times. He starts with this equation which i do understand how to get to.
$$
\begin{split}
\frac{d \langle x \rangle}{dt} = -\frac{i\hbar}{2m} \int\limits_{-\infty}^{\infty} x \cdot \frac{d}{dx} \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right) \, dx
\end{split}
$$
After 1st integration by parts he gets:
$$
\begin{split}
\frac{d \langle x \rangle}{dt} &= -\frac{i\hbar}{2m} \int\limits_{-\infty}^{\infty} \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right) \, dx
\end{split}
$$
After 2nd integration by parts he gets:
$$
\begin{split}
\frac{d \langle x \rangle}{dt} &= -\frac{i\hbar}{m} \int\limits_{-\infty}^{\infty} \frac{d \Psi}{dx}\Psi^* \, dx
\end{split}
$$
I tried to repeat the procedure but I get lost as soon as i try to do first intergation by parts. Only thing i managed to do is the procedure below which i have no clue what it means nor do i know how to continue. Could anyone shom e mow to do it?
$$
\frac{d \langle x \rangle}{dt} = -\frac{i\hbar}{2m} \int\limits_{-\infty}^{\infty} x \cdot \frac{d}{dx} \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right) \, dx = x \cdot x \cdot \frac{d}{dx} \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right) - \int\limits_{-\infty}^{\infty} x \,d \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right)
$$
$$
\begin{split}
\frac{d \langle x \rangle}{dt} = -\frac{i\hbar}{2m} \int\limits_{-\infty}^{\infty} x \cdot \frac{d}{dx} \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right) \, dx
\end{split}
$$
After 1st integration by parts he gets:
$$
\begin{split}
\frac{d \langle x \rangle}{dt} &= -\frac{i\hbar}{2m} \int\limits_{-\infty}^{\infty} \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right) \, dx
\end{split}
$$
After 2nd integration by parts he gets:
$$
\begin{split}
\frac{d \langle x \rangle}{dt} &= -\frac{i\hbar}{m} \int\limits_{-\infty}^{\infty} \frac{d \Psi}{dx}\Psi^* \, dx
\end{split}
$$
I tried to repeat the procedure but I get lost as soon as i try to do first intergation by parts. Only thing i managed to do is the procedure below which i have no clue what it means nor do i know how to continue. Could anyone shom e mow to do it?
$$
\frac{d \langle x \rangle}{dt} = -\frac{i\hbar}{2m} \int\limits_{-\infty}^{\infty} x \cdot \frac{d}{dx} \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right) \, dx = x \cdot x \cdot \frac{d}{dx} \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right) - \int\limits_{-\infty}^{\infty} x \,d \left( \frac{d \Psi^*}{dx} \Psi - \frac{d \Psi}{dx}\Psi^* \right)
$$