- #1
UrbanXrisis
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free fall with drag force
If the equation F=-bv^2 describes the drag force of an object...then the differential equation for the object's motion would be:
dv/dt= -g+bv/m
or is it...
dv/dt= g-bv/m
After solving the equation, should I get...
V=mg/b[1-e^(-bt/m)]
Also, does this look like the position v time graph of the object?
http://home.earthlink.net/~urban-xrisis/phy001.gif
If the equation F=-bv^2 describes the drag force of an object...then the differential equation for the object's motion would be:
dv/dt= -g+bv/m
or is it...
dv/dt= g-bv/m
After solving the equation, should I get...
V=mg/b[1-e^(-bt/m)]
Also, does this look like the position v time graph of the object?
http://home.earthlink.net/~urban-xrisis/phy001.gif
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