- #1
hasnain721
- 40
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[SOLVED] simple collisions question
http://img180.imageshack.us/img180/1253/28157442gm4.jpg
√(2gh)
a)
Gravitational potential energy = kinetic energy
this gives u
√(2gh)
= 0.815 metres
b)
i)
In a closed system, total momentum is always conserved.
ii)
Momentum before = momentum after
momentum before :
mass X velocity
(80/100) kg X 4 m/s = 0.32kgm/s
momentum after :
mass X velocity
((80/100) X 3) kg X x = 0.32 kgm/s
therefore x = 1.33 m/s
Is that rite?
and for c) :
ah i get it now!
Homework Statement
http://img180.imageshack.us/img180/1253/28157442gm4.jpg
Homework Equations
√(2gh)
The Attempt at a Solution
a)
Gravitational potential energy = kinetic energy
this gives u
√(2gh)
= 0.815 metres
b)
i)
In a closed system, total momentum is always conserved.
ii)
Momentum before = momentum after
momentum before :
mass X velocity
(80/100) kg X 4 m/s = 0.32kgm/s
momentum after :
mass X velocity
((80/100) X 3) kg X x = 0.32 kgm/s
therefore x = 1.33 m/s
Is that rite?
and for c) :
ah i get it now!
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