- #1
shravan
- 16
- 0
sin(a+b)/sin(a+c)=[ sin(2b)/sin(2c)]^(1/2)
then prove tan^2a=tanbtanc
I have reached till {tan(a)cos(b)+ sin(b)} * {sin(c)cos(c)}^(1/2)=
{tan(a)cos(c)+sin(c)}* { sin(b) cos(b)}^(1/2)
then prove tan^2a=tanbtanc
I have reached till {tan(a)cos(b)+ sin(b)} * {sin(c)cos(c)}^(1/2)=
{tan(a)cos(c)+sin(c)}* { sin(b) cos(b)}^(1/2)