Integral of squareroot and exponetial

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In summary, the conversation discusses a general method for integrating a specific type of integral involving the square root of a variable multiplied by an exponential function. The method involves substituting a new variable and using integration by parts to solve the integral. The conversation ends with confirmation that the method was successful.
  • #1
Mechdude
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1

Homework Statement


is there a general method of integrating this type of integral:
[tex] \int \sqrt{x -k} e^{-bx} [/tex]


Homework Equations





The Attempt at a Solution



[tex]x-k={u}^{2}[/tex]
[tex]dx=2udu[/tex]
[tex] \int u^2 \,{e}^{{-b\left( {u}^{2}-k\right) }}du [/tex]
[tex] \int {u}^{2}\,{e}^{{-b\,{u}^{2}}+{b\,k}}du [/tex]

and it seems worse than its starting point
 
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  • #2
Actually it's not worse... You can finish the problem by integrating by parts:

[tex]
\int u^2\,{e}^{-bu^2}=\int u\cdot u{e}^{-bu^2}
[/tex]

I don't know what happened but as I type my message, the browser won't process more tex-code, so I put it in raw form, but I hope, you can understand from it what I'm saying. So:

=u\cdot \frac{{e}^{-bu^2}}{-2b}+\frac 1{2b}\,\int {e}^{-bu^2}

And it's done, because the last integral can be calculated explicitly, see the Gauss-distribution at wikipedia.
 
  • #3
here's your code

[tex]=u\cdot \frac{{e}^{-bu^2}}{-2b}+\frac 1{2b}\,\int {e}^{-bu^2} [/tex]

thanks
i was able to do it :)
 

What is the integral of the squareroot function?

The integral of the squareroot function is equal to (2/3)x^(3/2) + C, where C is the constant of integration.

What is the integral of the exponential function?

The integral of the exponential function is equal to e^x + C, where C is the constant of integration.

Can the integral of the squareroot and exponential function be solved using substitution?

Yes, the integral can be solved using substitution by letting u be equal to the expression inside the squareroot or exponential function.

What is the difference between indefinite and definite integrals?

An indefinite integral does not have specified upper and lower limits, while a definite integral has specific values for the upper and lower limits of integration.

How can the integral of the squareroot and exponential function be applied in real life?

The integral can be used to find the area under a curve in various fields such as physics, engineering, and economics. It can also be used to calculate the growth of populations and the decay of radioactive substances.

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