- #1
Paddyod1509
- 10
- 0
the damped oscillator equation:
(m)y''(t) + (v)y'(t) +(k)y(t)=0
Show that the energy of the system given by
E=(1/2)mx'² + (1/2)kx²
satisfies:
dE/dt = -mvx'
i have gone through this several time simply differentiating the expression for E wrt and i end up with
dE/dt = x'(-vx')
im at a brick wall. Am i doing something wrong? Any help is much appreciated! Thanks
(m)y''(t) + (v)y'(t) +(k)y(t)=0
Show that the energy of the system given by
E=(1/2)mx'² + (1/2)kx²
satisfies:
dE/dt = -mvx'
i have gone through this several time simply differentiating the expression for E wrt and i end up with
dE/dt = x'(-vx')
im at a brick wall. Am i doing something wrong? Any help is much appreciated! Thanks