- #1
yshtar
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I need help in understanding a rectifier to charge a lead acid battery on my bike. I checked it with an ohm meter to see where the current flowed, like this:
--- I put the positive on Pin 1 and the negatives on Pin 2, 3, and 4 and they connected. So, the current goes from Pin 1 to Pin 2, 3 and 4. (Am I right?)
--- Positive on Pin 2, the current goes to Pin 4.
--- Positive on Pin 3, the current goes to Pin 4.
Now Pin 1 is connected to the positive on the battery, and Pin 4 to the negative.
One end of the pulse generator is connected to Pin 4 (and the negative of the battery), and the other end is connected to Pin 2 (or Pin 3, since they have the same direction).
From what I understand, the positive charge should go out from Pin 4, and it should be connected to the positive of the battery, and Pin 1 to the negative of the battery. But when I did it, the battery lost power.
I checked with the DC volt meter, and placed the positive pin on Pin 1 and I got about one volt, so the current seemed to go out from Pin 1.
Any help will be appreciated. Very confused here.Thanks in advance.
--- I put the positive on Pin 1 and the negatives on Pin 2, 3, and 4 and they connected. So, the current goes from Pin 1 to Pin 2, 3 and 4. (Am I right?)
--- Positive on Pin 2, the current goes to Pin 4.
--- Positive on Pin 3, the current goes to Pin 4.
Now Pin 1 is connected to the positive on the battery, and Pin 4 to the negative.
One end of the pulse generator is connected to Pin 4 (and the negative of the battery), and the other end is connected to Pin 2 (or Pin 3, since they have the same direction).
From what I understand, the positive charge should go out from Pin 4, and it should be connected to the positive of the battery, and Pin 1 to the negative of the battery. But when I did it, the battery lost power.
I checked with the DC volt meter, and placed the positive pin on Pin 1 and I got about one volt, so the current seemed to go out from Pin 1.
Any help will be appreciated. Very confused here.Thanks in advance.
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