- #1
Bassalisk
- 947
- 2
http://pokit.org/get/8119a4b8a37171c67971c3fb13b33063.jpg
Consider picture above.
I understand how an integrator behaves when the capacitor is full. It(capacitor) acts as infinite resistance ergo open loop so we get positive saturation at the output.
What I don't understand how come we are starting at 0? Doesn't capacitor act like a short circuit in the very first moments of its charging? Effectively making this a voltage follower? (at very first moments). I understand what voltage follower does in situation when the Vin is connected to + lead and we have short circuit between output and - lead. Question risen what would happen if I grounded a + lead and connected Vin to - through a resistor like so:
http://pokit.org/get/4b7a8c8dca68aacc548f3a3b2d748715.jpg
Have I just short circuited the whole op-amp? As it isn't there?
Getting weird results from simulations.
Consider picture above.
I understand how an integrator behaves when the capacitor is full. It(capacitor) acts as infinite resistance ergo open loop so we get positive saturation at the output.
What I don't understand how come we are starting at 0? Doesn't capacitor act like a short circuit in the very first moments of its charging? Effectively making this a voltage follower? (at very first moments). I understand what voltage follower does in situation when the Vin is connected to + lead and we have short circuit between output and - lead. Question risen what would happen if I grounded a + lead and connected Vin to - through a resistor like so:
http://pokit.org/get/4b7a8c8dca68aacc548f3a3b2d748715.jpg
Have I just short circuited the whole op-amp? As it isn't there?
Getting weird results from simulations.
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