- #1
ian_durrant
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[SOLVED] Acceleration/Velocity Problem
Two students, Anne and Joan, are bouncing straight up and down on a trampoline. Anne bounces 2.61 times as high as Joan does. Assuming both are in free-fall, find the ratio of the time Anne spends between bounces to the time Joan spends.
y=V(0)t+ (1/2)gt^2
Ok I figured that if Anne is jumping 2.61 times as high as Joan, I could set y (the displacement) as 2.61 for Anne and 1 for Joan. However I plugged the numbers into the equation and ended up getting a negative answer for my time, which doesn't make sense. Here's my equations that I used:
Anne-
2.61=(1/2)(-9.8)t^2
-.53=t^2
Joan-
1=(1/2)(-9.8)t^2
-.204=t^2
I figured what I would do after i got the time is to multiple them both by 2 since I only calcuated them returning for the highest point to lowest point, then plugging them into a ratio. Any thoughts?
Homework Statement
Two students, Anne and Joan, are bouncing straight up and down on a trampoline. Anne bounces 2.61 times as high as Joan does. Assuming both are in free-fall, find the ratio of the time Anne spends between bounces to the time Joan spends.
Homework Equations
y=V(0)t+ (1/2)gt^2
The Attempt at a Solution
Ok I figured that if Anne is jumping 2.61 times as high as Joan, I could set y (the displacement) as 2.61 for Anne and 1 for Joan. However I plugged the numbers into the equation and ended up getting a negative answer for my time, which doesn't make sense. Here's my equations that I used:
Anne-
2.61=(1/2)(-9.8)t^2
-.53=t^2
Joan-
1=(1/2)(-9.8)t^2
-.204=t^2
I figured what I would do after i got the time is to multiple them both by 2 since I only calcuated them returning for the highest point to lowest point, then plugging them into a ratio. Any thoughts?