- #1
jahlin
- 21
- 0
Homework Statement
whats the equation of a straight line passing through (1,4) and (5,1)?
Homework Equations
y=mx+c
The Attempt at a Solution
i found the equation to be y=-(3/4)x is it right?
Thanks
The equation of a straight line is represented in the form y = mx + b, where m is the slope of the line and b is the y-intercept. This equation can also be written as Ax + By = C, where A and B are the coefficients of x and y, and C is a constant.
The slope of a straight line is the rate of change between any two points on the line. It can be calculated by taking the difference in y-coordinates divided by the difference in x-coordinates, or (y2 - y1) / (x2 - x1). This can also be represented as rise over run.
The y-intercept is the point where the line crosses the y-axis. It represents the initial value of y when x is equal to 0. In other words, it is the value of y when x is not present in the equation. The y-intercept can also indicate the starting point or the initial condition of a function or relationship.
No, the equation of a straight line only represents linear relationships. Nonlinear relationships can be represented using other types of equations such as quadratic, exponential, or logarithmic.
To graph a straight line using its equation, plot the y-intercept first, and then use the slope to find one or more additional points on the line. Connect these points with a straight line to create the graph. Alternatively, you can use the slope-intercept form (y = mx + b) to graph the line by plotting the y-intercept and using the slope to find other points or by using the point-slope form (y - y1 = m(x - x1)) and a specific point on the line to graph it.