- #1
semidevil
- 157
- 2
so I need to show that in any group, it's elements and inverse has the same order.
so can I say that since it is a group, we know that there exists a unique inverse for each element. So each element would have 1 inverse. And then, that means we have the same number of elements as number of inverses?
does that work? or am I missing something?
so can I say that since it is a group, we know that there exists a unique inverse for each element. So each element would have 1 inverse. And then, that means we have the same number of elements as number of inverses?
does that work? or am I missing something?