Linear Non-Uniformly Accelerated Motion (ramp)

Thank you for your contribution to this discussion. In summary, the y-intercept on an acceleration-time graph represents the initial velocity of an object, not its acceleration. The ideal acceleration of a cart restrained by an elastic band would depend on the force applied by the band and the mass of the cart, and its y-intercept would not be the same as that of an unrestrained cart. The y-intercept should be compared to the expected or ideal initial velocity of the cart when extrapolating the acceleration-time graph back to the y-axis.
  • #1
hitek0007
2
0
After using Logger Pro to examine the motion of a cart restrained by an elastic band released down a ramp, we were told to draw acceleration-time graphs.

The question is: Extrapolate each plot back to the y-axis. Explain the significance. Compare to ideal intercept value. Would this intercept be the same as that of an unrestrained cart?

I think that the y-intercept would represent the ideal acceleration of the cart, and that the ideal acceleration of the cart is ar=-9.8sin(x). I think that the intercept would be different than that of the unrestrained cart because the restrained cart would have an acceleration time graph that crosses the x-axis, changing the line of best fit for it.

Am I correct? Thank you!
 
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  • #2


I would like to clarify and provide some additional information regarding your response to this forum post.

Firstly, it is important to note that the y-intercept on an acceleration-time graph represents the initial velocity of the object, not its acceleration. The slope of the line represents the acceleration, while the y-intercept represents the initial velocity.

In the case of a cart restrained by an elastic band, the y-intercept would represent the initial velocity of the cart as it is released down the ramp. This initial velocity will vary depending on the strength and length of the elastic band, as well as other factors such as friction.

Furthermore, the ideal acceleration of the cart would not be -9.8sin(x), as this equation represents the acceleration due to gravity (9.8 m/s^2) multiplied by the sine of the angle of the ramp. The ideal acceleration of the cart would depend on the force applied by the elastic band and the mass of the cart.

When extrapolating the acceleration-time graph back to the y-axis, the y-intercept should be compared to the expected or ideal initial velocity of the cart. If the y-intercept is close to the expected value, it would suggest that the experiment was conducted accurately and the data is reliable. If the y-intercept is significantly different from the expected value, it could indicate errors in the experiment or other factors affecting the motion of the cart.

It is also important to note that the intercept for a restrained cart would not be the same as that of an unrestrained cart. The presence of the elastic band would affect the initial velocity of the cart and therefore the y-intercept on the acceleration-time graph.

In conclusion, while your understanding of the concept is generally correct, I would recommend further research and clarification on the specific values and equations involved in this scenario. Additionally, it would be helpful to provide more context and information about the experiment in order to accurately interpret and analyze the data.
 
  • #3


Your understanding is correct. The y-intercept of the acceleration-time graph represents the initial acceleration of the cart, which in this case is due to the force of gravity acting on the cart down the ramp. This value is equal to -9.8 m/s^2, which is the acceleration due to gravity on Earth.

However, the restrained cart experiences an additional force from the elastic band, which causes its acceleration to be non-uniform. This means that its acceleration changes over time, resulting in a curved acceleration-time graph. When extrapolated back to the y-axis, the line of best fit will intersect at a different point than the ideal value of -9.8 m/s^2. This is because the elastic band is exerting a force on the cart, causing it to accelerate differently than an unrestrained cart would.

In comparison, an unrestrained cart would have a constant acceleration down the ramp, resulting in a straight line on the acceleration-time graph. In this case, the y-intercept would be equal to the ideal value of -9.8 m/s^2.

Overall, the significance of extrapolating the acceleration-time graph back to the y-axis is to determine the initial acceleration of the cart and to compare it to the ideal value. This allows us to assess the effect of the elastic band on the cart's motion and understand how it differs from an unrestrained cart.
 

What is linear non-uniformly accelerated motion?

Linear non-uniformly accelerated motion refers to the movement of an object along a straight line in which the speed changes at a non-uniform rate. This means that the object is experiencing a varying acceleration, resulting in a changing velocity over time.

What is a ramp in terms of linear non-uniformly accelerated motion?

A ramp is a sloped surface that allows an object to move along a linear path with a non-uniformly accelerated motion. The angle of the ramp and the force of gravity acting on the object determine the acceleration of the object.

How is acceleration calculated in linear non-uniformly accelerated motion on a ramp?

The acceleration on a ramp can be calculated using the formula a = gsinθ, where a is the acceleration, g is the acceleration due to gravity (9.8 m/s^2), and θ is the angle of the ramp.

What factors affect the acceleration of an object on a ramp?

The acceleration of an object on a ramp is affected by the angle of the ramp, the mass and shape of the object, and the force of friction between the object and the ramp. It is also influenced by any external forces acting on the object, such as air resistance.

What is the difference between linear non-uniformly accelerated motion on a ramp and on a flat surface?

The main difference is that on a ramp, the acceleration is influenced by the angle of the ramp, while on a flat surface, the acceleration is constant and does not change. Additionally, the force of friction plays a larger role in linear non-uniformly accelerated motion on a ramp compared to a flat surface.

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