- #1
kasse
- 384
- 1
I just came across the eq.
z^2 - 2z + 1 - 2i
where z is a complex number. How do I solve this sort of eq.?
I tried to solve it as a normal 2nd degree eq., setting a=2, b=-2 and c=(1-2i), with z as the variable. This finally gave me the solutions
z(1) = -1 + sqrt(2i)
and
z(2) = -1 - sqrt(2i)
Can this be the correct solution? I had hoped for an answer involving i, not sqrt(i)...
z^2 - 2z + 1 - 2i
where z is a complex number. How do I solve this sort of eq.?
I tried to solve it as a normal 2nd degree eq., setting a=2, b=-2 and c=(1-2i), with z as the variable. This finally gave me the solutions
z(1) = -1 + sqrt(2i)
and
z(2) = -1 - sqrt(2i)
Can this be the correct solution? I had hoped for an answer involving i, not sqrt(i)...