- #1
parwana
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last question
Calculate the energy change for the formation in kJ of 0.39 mol of KI(s)
given the following information: I2(s) --> I2(g) : 62.44 KJ/mol
K(s) --> K(g) : 180.4 KJ/mol
1/2 I2(g) -->I(g) : 138.05 KJ/mol
K+(g) + e- --> K(g) : -419 KJ/mol
I-(g) --> I(g) + e- : 295.16 KJ/mol
Lattice energy for KI = -649 KJ/mol
E= E(vaporization)+IE+1/2bond energy+EA+lattice energy
how would i do this, should i just add everything up?? but then what about the .39 mol??
Calculate the energy change for the formation in kJ of 0.39 mol of KI(s)
given the following information: I2(s) --> I2(g) : 62.44 KJ/mol
K(s) --> K(g) : 180.4 KJ/mol
1/2 I2(g) -->I(g) : 138.05 KJ/mol
K+(g) + e- --> K(g) : -419 KJ/mol
I-(g) --> I(g) + e- : 295.16 KJ/mol
Lattice energy for KI = -649 KJ/mol
E= E(vaporization)+IE+1/2bond energy+EA+lattice energy
how would i do this, should i just add everything up?? but then what about the .39 mol??