Finding Equations of Tangents and Intersection Points for y=(2x-1)(x+1)

  • Thread starter emmab
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In summary, to find the equations of the tangents to the curve y=(2x-1)(x+1) at the points where the curve cuts the x axis, you can either first find the tangent equation using differentiation and then find the points of intersection, or you can find the x-values where the curve crosses the x-axis and then find the derivative at those values of x. Both methods will yield the same result.
  • #1
emmab
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0
additional maths help please!

My minds gone blank. How do I solve this
Find the equations of the tangents to the curve y=(2x-1)(x+1) at the points where the curve cuts the x axis. Find the point of intersection of these tangents.
Thanks
Emmab
 
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  • #2


First find the tangent equation using differentiation, then find the points where the curve cuts the x-axis and plug in.
 
  • #3


I would be inclined to do it the other way around! First find the x-values where the curve crosses the x-axis (y= 0 there), then find the derivative at those values of x. No real difference, of course.
 

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