Constructive Interference Problem with 2 Speakers

In summary, the problem involves standing a distance of 1 m from two identical speakers, driven by the same source, that are 3 m apart. The speed of sound is 340 m/s and the frequency is 170 Hz. The question asks how many times and where a maximum sound will be heard as you walk along a line parallel to the line of the two speakers. One approach to solving this problem is to plot the path difference as a function of y, using the given values of d and h, and using the graph to determine the values of y where maximum sound will be heard.
  • #1
infamous24
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Homework Statement


You are standing a distance d (1 m) in front of one of two identical speakers, being driven by the same source, that are a distance h (3 m) apart. You walk (starting at y=0) along a line parallel to the line of the two speakers. The speed of sound is 340 m/s and the frequency is 170 Hz.

Question: As you walk, how many times and where will you hear a maximum sound?

Homework Equations


ΔФ= 2λ/m + ΔФo


The Attempt at a Solution



I solved the above equation for the variables y and m, but I am unable to solve the equation to find what values of y where a maximum sound will be heard. My teacher suggested to make a plot of the path difference as a function of y using the given d and h and use the graph to determine the values of y which satisfy the maximum sound condition.
 
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Welcome to PF forums! If you've already taken a look around, you will notice there are many interesting and informative topics around this site. And also people willing to offer their expertise and guidance on questions.

Your teacher's suggestion is a sound approach (no pun intended). Perhaps you can draw a picture of what the problem states, indicating the direction you are moving, relative to the speakers and be sure to show the relative dimensions along the axis between the speakers and then post it here. Also show the shape of a waveform, as it is radiated from each speaker.
 
  • #3
However, I am not sure what values of y to plot and how to interpret the graph to find the solutions.

As a scientist, it is important to understand and interpret data in order to solve problems. In this case, the maximum sound condition can be achieved when the path difference between the two speakers is an integer multiple of the wavelength. This is known as constructive interference, where the sound waves from the two speakers reinforce each other.

To solve this problem, we can use the formula ΔФ = 2λ/m + ΔФo, where ΔФ is the path difference, λ is the wavelength, m is the integer multiple, and ΔФo is the initial phase difference. In this case, the initial phase difference is 0, since both speakers are driven by the same source.

First, we need to find the wavelength of the sound wave, which can be calculated using the formula λ = v/f, where v is the speed of sound and f is the frequency. Plugging in the given values, we get λ = 340/170 = 2 m.

Next, we can plot the path difference as a function of y, where y represents the distance you walk from the initial position. The path difference formula can be rewritten as ΔФ = 2y/h + ΔФo. We can choose a few values of y and plot them on the graph, such as y = 0, 1, 2, 3, etc. The graph should look like a straight line with a slope of 2/h.

Now, we need to determine at which values of y the path difference is an integer multiple of the wavelength. These values will correspond to the locations where constructive interference occurs. In this case, the path difference needs to be equal to an integer multiple of 2 m.

For example, if we choose y = 2, the path difference is 2(2)/3 + 0 = 4/3 m, which is not an integer multiple of 2 m. However, if we choose y = 3, the path difference becomes 2(3)/3 + 0 = 2 m, which is exactly one wavelength. This means that at y = 3, you will experience constructive interference and hear a maximum sound.

Similarly, we can choose other values of y and determine at which points constructive interference occurs. The number of times you will hear a maximum sound will depend on how far you walk and the
 

1. What is constructive interference?

Constructive interference occurs when two or more waves meet and their amplitudes combine to create a larger wave. This is due to the waves being in phase, meaning their peaks and troughs align, resulting in a stronger combined wave.

2. How does constructive interference affect sound waves?

In the context of sound waves, constructive interference can result in a louder and clearer sound. When two speakers are placed close together and emit sound waves that are in phase, the resulting constructive interference will create a more powerful and cohesive sound.

3. Why does constructive interference occur with only two speakers?

Constructive interference can occur with any number of waves, but when there are only two sources, the waves are more likely to be in phase and create a stronger interference pattern. With more than two sources, it is more difficult to align all the waves perfectly.

4. How can constructive interference be a problem with two speakers?

In some cases, constructive interference can be a problem when two speakers are placed too close together. If the waves are not perfectly in phase, the resulting interference can create areas of reinforcement and cancellation, leading to an uneven and distorted sound.

5. How can the problem of constructive interference be solved?

To solve the problem of constructive interference with two speakers, they can be placed further apart to decrease the likelihood of the waves being in phase. Additionally, adjusting the positioning and angle of the speakers can also help to reduce interference and create a more balanced sound.

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