- #1
MathWarrior
- 268
- 5
y' = (x)/(1+2y)
y(-1) = 0
trying to find the answer I do the following:
multiply both sides by (1+2y)
(1+2y) * dy/dx = x
i subtract 1 from both sides.. but for some reason this is wrong? why?
2y * dy/dx = x - 1
2y dy = x-1 dx
integrate..
y^2 = (x^2-x+C)/2
y = sqrt((x^2-x+C)/2) )
this however is wrong I was not suppose to subtract the 1 from both sides.. what exactly is wrong with doing that?
y(-1) = 0
trying to find the answer I do the following:
multiply both sides by (1+2y)
(1+2y) * dy/dx = x
i subtract 1 from both sides.. but for some reason this is wrong? why?
2y * dy/dx = x - 1
2y dy = x-1 dx
integrate..
y^2 = (x^2-x+C)/2
y = sqrt((x^2-x+C)/2) )
this however is wrong I was not suppose to subtract the 1 from both sides.. what exactly is wrong with doing that?
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