Heat Transfer Through a Cylinder

[CanoIsDbo]

The problem is about a cylinder with 3 mm thickness in the walls, roof, and ceiling. The walls, roof, and ceiling also have a k value of .0042 w/mk. Inside the cylinder is 64 degrees Celsius and outside its 22 degrees Celsius. The air outside the cylinder has a heat transfer coefficient of .3 W/m^2K. I have to calculate the heat loss for this cylinder. My question is, how do I add the resistances for the walls, ceiling/base, and air? Would it be delta T/(Rwall, Rceiling/base, Rair(wall), Rair(base/ceiling))?

 

[teknodude]

Can you post the actual problem statement?

I think if you draw a thermal circuit, it will give you a good map to solve the problem.

 

[piercas]

To calculate the heat loss for this cylinder, you would need to use the formula Q = U x A x ΔT, where Q is the heat loss, U is the overall heat transfer coefficient, A is the surface area, and ΔT is the temperature difference between the inside and outside of the cylinder.

In order to determine the overall heat transfer coefficient, you would need to add the individual resistances for the walls, ceiling/base, and air. The formula for calculating the overall heat transfer coefficient is U = 1/(Rwall + Rceiling/base + Rair(wall) + Rair(base/ceiling)).

To calculate the individual resistances, you would use the formula R = L/(k x A), where R is the resistance, L is the thickness of the material, k is the thermal conductivity, and A is the surface area. You would need to calculate the resistance for each component (walls, ceiling/base, and air) and then add them together to get the overall heat transfer coefficient.

Once you have calculated the overall heat transfer coefficient, you can plug it into the formula Q = U x A x ΔT to calculate the heat loss for the cylinder.