Is My Matrix Calculation Correct for Composite Reflections in Linear Algebra?

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In summary, the standard matrix of the transformation T is given by:\begin{bmatrix}0 & 1\\ 1 & 0\end{bmatrix}\begin{bmatrix}1 & 0\\ 0 & -1\end{bmatrix} = \begin{bmatrix}0 & -1\\ 1 & 0\end{bmatrix}
  • #1
flyingpig
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Homework Statement



Find the standard matrix of T

[tex]T: \mathbb{R}^2 \to \mathbb{R}^2 [/tex] first reflects points through the horizontal x1 axis and then reflects points through the line x2 = x1


The Attempt at a Solution



I almost always have to look at my book to remind myself what the standard matrix transformation for each transformation is

So I did

e1 becomes (which I will use [tex]\to[/tex]) [tex]\to[/tex] e1 (which doesn't change [tex]\to[/tex] e2

That's column one. Also I am using David Lay's book, so I don't know words like "nullspace", "basis", etc...

[tex]e_2 \to -e_2 \to -(e_1)[/tex]

Then I get

[tex]\begin{bmatrix}
0 & -1\\
1 & 0
\end{bmatrix}[/tex]

Now my question is, am I right about the [tex]-(e_1)[/tex]? I added brackets on purpose
 
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  • #2
Yes, that's right. Note that this matrix, with both transformations, is the product of two matrices:
[tex]\begin{bmatrix}0 & 1\\ 1 & 0\end{bmatrix}\begin{bmatrix}1 & 0\\ 0 & -1\end{bmatrix}[/tex]
Let's call these matrices A and B, where A reflects across the line y = x (i.e., it switches the x and y coordinates) and B reflects across the x-axis.

The transformation that reflects across the x-axis and then reflects across the line y = x, can be expressed as the product of A and B, in that order. The expression ABv is evaluated as A(Bv), where Bv reflects v across the x-axis, and then A reflects the vector Bv across the line y = x.
 

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