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Homework Statement
(b) Fig. Q.6 shows a belt drive system where pulley A (diameter 0.5 m) is transmitting power to pulley B (diameter 0.25 m), mounted on a parallel rotating shaft. The tight and slack-side tensions of the belt are 500 N and 200 N respectively, and pulley A rotates at 300 rev/min.
Determine
(i) The linear speed of the belt (in m/s))
(ii) The rotational speed of pulley B (in rev/min)
(iii) The torque on pulley B.
(iv) The power transmitted to pulley B.
The Attempt at a Solution
(i)
To find linear speed in (m/s)
v= RxW
V=0.5x(300x(2pi/60))
v=0.5x31.4159
v=15.7079m/s
(II)
the rotational speed of pully B
if
0.5m = 300rev/min
therefore
300/0.5 = 600
600x0.25= 150rev/min
(iii)
To find torque
Tb=(f1-f2)Rb
Tb=(500-200)0.125
Tb=(300)0.125
Tb=37.5Nm
(iv)
To find power
Pb=TbxWb
Pb=37.5x(150x(2pi/60))
Pb=589.04watts
i did my best, can some one tell me if I am on the right track or I am totaly off
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