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Tony11235
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How am supposed to calculate the five longest wavelengths of the Lyman series? What values of n are used? I see how you arrive at a definite limit as n goes to infinity, but the five longest? Sort of a dumb question.
The formula for calculating the wavelengths of the 5 longest Lyman series is λ = R(1/nf² - 1/ni²), where λ is the wavelength, R is the Rydberg constant, and nf and ni are the final and initial energy levels, respectively.
The Rydberg constant is a fundamental physical constant that appears in the relationships between the energy levels of atoms, particularly in the Balmer, Lyman, and Paschen series. Its value is approximately 1.0974 x 107 m-1.
The final and initial energy levels for the Lyman series can be determined by using the equation n = 1, 2, 3, ... where n is the principal quantum number. The final energy level is always n = 1, and the initial energy levels for the 5 longest Lyman series are n = 2, 3, 4, 5, and 6.
No, the formula for calculating the 5 longest Lyman series wavelengths is specific to hydrogen atoms and will not work for other atoms.
The calculated wavelengths for the 5 longest Lyman series can be verified experimentally by using a spectrometer to measure the actual wavelengths emitted by hydrogen atoms. The experimental values can then be compared to the calculated values to determine the accuracy of the calculation.