- #1
tomboi03
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As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is Lw. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g.
Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward).
So the known variables are... t, Lw, and g.
If the bottom of your window is a height h above the ground, what is the velocity vground of the pot as it hits the ground? You may introduce the new variable vb , the speed at the bottom of the window, defined by
Vb=Lw/t+(g*t)/2.
Express your answer in terms of some or all of the variables hb, Lw, t, vb, and g.
I have these equations already... but i don't know where to go about from here...
hb=vb+1/2(gt2)
the equation given...
vg=vb+g*t
vb=1/2*g*t2-hb
I keep missing one variable... and I'm getting frustrated... :'(
Please help me out.
Thank You,
tomboi03
Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward).
So the known variables are... t, Lw, and g.
If the bottom of your window is a height h above the ground, what is the velocity vground of the pot as it hits the ground? You may introduce the new variable vb , the speed at the bottom of the window, defined by
Vb=Lw/t+(g*t)/2.
Express your answer in terms of some or all of the variables hb, Lw, t, vb, and g.
I have these equations already... but i don't know where to go about from here...
hb=vb+1/2(gt2)
the equation given...
vg=vb+g*t
vb=1/2*g*t2-hb
I keep missing one variable... and I'm getting frustrated... :'(
Please help me out.
Thank You,
tomboi03