- #1
jybe
- 41
- 1
Homework Statement
A flower pot is knocked off a window ledge from a height
d = 21.6 m
above the sidewalk as shown in the figure below. It falls toward an unsuspecting man of height
h = 1.71 m
who is standing below. Assume the man below requires 0.300 s to respond to a warning. How close to the sidewalk can the flowerpot fall before it is too late for a warning shouted from the balcony to reach the man in time? (Use 343 m/s for the speed of sound.)
Homework Equations
h = 0.5gt^2
The Attempt at a Solution
Time it takes sound to reach the man = (21.7-1.71)/343 = 0.057988 seconds
Time it takes the flowerpot to reach the man: (21.6-1.71) = (0.5)(9.8)t^2
t = 1.7147 seconds to reach the man
So he needs a warning at (1.7147 - 0.3 - 0.057988) = 1.356712 seconds
h = 0.5(9.8)(1.356712)^2
h = 9.0193 m
(21.6 - 9.0193) = 12.5807 m
So my answer is that it can get 12.5807 m to the sidewalk before it's too late for a warning.
This answer may or may not be correct (I keep getting it wrong, I'm more confident about this time but I don't want to submit it because I have limited attempts). Can anybody verify this for me? Thanks a lot