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Drawing a simple vector field issue 
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#1
Mar2207, 12:01 PM

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Hello everyone i'm not sure if this is right or not...
If i have F(x,y,z) = zj; where j is the vector, j hat. Would that be all vectors are going to be pointing up if you assume z is up, and are in the y plane? If the coordinate sytem is, z is up, y is to the right, and x is pointing at you. If i had F(x,y,z) = yj; the answer is, No vectors emanate from the xz plane since y = 0 there. In each plane y = b, all the vectors are identical. 


#2
Mar2207, 12:44 PM

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No. j is a unit vector pointing in the same direction as the +y axis. Which you seem to want to call 'right'. The length of the vectors is proportional to their z coordinate. What is the 'y plane'? What does 'in' a plane mean? Parallel to?



#3
Mar2207, 12:53 PM

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I worked it out and it seems the vectors are pointing parrallel to the +y axis which is pointing right, for values > 0, and for values < 0 its pointing to the left or in the y direction.



#4
Mar2207, 12:57 PM

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Drawing a simple vector field issue



#5
Mar2207, 01:52 PM

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z is a number, j is a vector pointing in the positive y direction. Your vector field consists of vector pointing in the positive y direction, longer as z increases. (And pointing in the negative y direction for z negative.)



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