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Drawing a simple vector field issue

by mr_coffee
Tags: drawing, field, issue, simple, vector
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mr_coffee
#1
Mar22-07, 12:01 PM
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Hello everyone i'm not sure if this is right or not...

If i have

F(x,y,z) = zj; where j is the vector, j hat.

Would that be all vectors are going to be pointing up if you assume z is up, and are in the y plane?


If the coordinate sytem is, z is up, y is to the right, and x is pointing at you.

If i had F(x,y,z) = yj; the answer is, No vectors emanate from the xz plane since y = 0 there. In each plane y = b, all the vectors are identical.
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Dick
#2
Mar22-07, 12:44 PM
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No. j is a unit vector pointing in the same direction as the +y axis. Which you seem to want to call 'right'. The length of the vectors is proportional to their z coordinate. What is the 'y plane'? What does 'in' a plane mean? Parallel to?
mr_coffee
#3
Mar22-07, 12:53 PM
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I worked it out and it seems the vectors are pointing parrallel to the +y axis which is pointing right, for values > 0, and for values < 0 its pointing to the left or in the -y direction.

Dick
#4
Mar22-07, 12:57 PM
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Drawing a simple vector field issue

Quote Quote by mr_coffee View Post
I worked it out and it seems the vectors are pointing parrallel to the +y axis which is pointing right, for values > 0, and for values < 0 its pointing to the left or in the -y direction.
That's the right picture (where 'values' means z, right).
HallsofIvy
#5
Mar22-07, 01:52 PM
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z is a number, j is a vector pointing in the positive y direction. Your vector field consists of vector pointing in the positive y direction, longer as z increases. (And pointing in the negative y direction for z negative.)


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