# box on a Toboggan - Newton's Laws

by NKKM
Tags: laws, newton, toboggan
 P: 8 1. The problem statement, all variables and given/known data HI, I am confused about how to approach this question. A 4.0 kg toboggan rests on a frictionless icy surface, and a 2.0 kg block rests on top of the toboggan. The coefficient of static friction m s between the block and the surface of the toboggan is 0.60, whereas the kinetic friction coefficient is 0.51. The block is pulled by a 30 N-horizontal force as shown. What are the magnitudes and directions of the resulting accelerations of the block and the toboggan? 2. Relevant equations Fpull- Ffriction = Fnet = ma Ffriction = uk X Fnormal Fnormal = mg 3. The attempt at a solution If I calculate the acceleration of the box as so: Fpull- Ffriction = Fnet = ma using the kinetic friction coefficient and solve for acceleration. Does that make sense.. and how then do I approach the acceleration of the toboggan? Would it slide under the box?
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