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Calculating 0.2% proof stress of aluminium 
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#19
Jan208, 01:53 PM

P: 12

i see your point however i am basing my calculations on what one of my lecturers emailed me~:~
"If, for example, your horizontal axis shows 5.0mm of extension, and you measure this as being say 220mm, it follows that 1mm in reality is represented by 44mm on your axis (220 divided by 5) Now multiply 0.2% of gauge length by 44 to obtain the amount of offset " 


#20
Jan208, 02:00 PM

Sci Advisor
P: 2,283

CS 


#21
Mar2808, 11:59 PM

P: 1

i thought the graph should be stressstrain graph? why is it forceelongation graph? is it the same/?



#22
Apr411, 06:13 AM

P: 1

Strain is Elongation/Original test piece Length The two graphs are not the same, but the shapes are identical, as the original area and original length are constant. But that is a good point, why isn't your graph a StressStrain one? 


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