## Simple Calculus Word Problem (using derivatives to anaylze function models)

Hello, new here, first post. Just need some help with homework.

Question One

1. The problem statement, all variables and given/known data

This norman window is made up of a semicircle and a rectangle. The total perimeter of the window is 16 cm. What is the maximum area?

**
* * <<< Semicircle
*****
| | <<< Rectangle
L | |
______
D
2. Relevant equations

P (total) = 2L + D + (pi * d)

A (total) = D * L + (pi(d/2)^2)/2)

3. The attempt at a solution

What I did was using this equation:
16 = 2L + D + ((pi * d)/2)
L = 8 - d/2 - ((pi * d)/4)

A = D (8 - d/2 - ((pi * d)/4)) + (pi (d/2)^2)/2)
A = 8d - (d^2)/2
A' = 8 - d
Let 0 = A' to find critical value
then 8 = d.

When I sub that back into the original equation, I get L as a value less than 8, which doesn't make sense. (I think it works out to be L = 4 - pi)

I'm pretty much lost, sorry if this is too messy to read, any help would be appreciated. Thanks
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 Recognitions: Homework Help Science Advisor You made a great start. But where did you get "16 = 2L + D + ((pi * d)/2)"?? The "/2" wasn't in your original expression for P. You are just making algebraic mistakes.
 I think you're doing fine up until this point: A = D (8 - d/2 - ((pi * d)/4)) + (pi (d/2)^2)/2) Which should simplify into $$A = 8*D - \frac{D^2}{2} - \frac{pi*D^2}{4} + \frac{pi*D^2}{8}$$ You would then go on to take the derivate and then set it to zero and solve for your D value I've been beaten =(

## Simple Calculus Word Problem (using derivatives to anaylze function models)

 Quote by Dick You made a great start. But where did you get "16 = 2L + D + ((pi * d)/2)"?? The "/2" wasn't in your original expression for P. You are just making algebraic mistakes.
ah sorry, its actually supposed to be "/2", that way its half the area, sorry the drawing didnt show up. its supposed to be a semi-circle connected to a rectangle.

 Quote by RyanSchw I think you're doing fine up until this point: A = D (8 - d/2 - ((pi * d)/4)) + (pi (d/2)^2)/2) Which should simplify into $$A = 8*D - \frac{D^2}{2} - \frac{pi*D^2}{4} + \frac{pi*D^2}{8}$$ You would then go on to take the derivate and then set it to zero and solve for your D value I've been beaten =(
sorry, that was a typing error as well haha.

A = L * D + (pi*d)/2
which becomes

A = 8 - d/2 - ((pi * d)/4)

this still doesnt work...I think i'm using the wrong equations somehow
 Recognitions: Homework Help Science Advisor Why isn't there a D in all of the terms of A? I think you understand this problem perfectly well and you are using the right equations. You are simply making typographical mistakes right and left. Get a clean sheet of paper, calm down and take a stress pill and you can do this.