Explain the proof in goldstein

AI Thread Summary
The discussion focuses on analyzing the motion of a bead on a rotating wire using the Lagrangian formulation. The generalized coordinate is the distance along the wire, leading to the application of Lagrange's equation. The key point is that the generalized force Q is zero because the constraint of the bead moving along the wire is incorporated into the generalized coordinates, and there are no non-conservative forces like friction. This results in the simplification where the kinetic energy T equals the Lagrangian L, as there is no potential energy involved. The proof illustrates the application of Lagrangian mechanics in constrained systems.
pardesi
Messages
337
Reaction score
0
Question:
Analyze the motion of a small bead attached to a wire which is rotating along a fixed axis?

Proof(Using Lagrangian formulation):
Clearly here the generalized coordinate is the distance of the particle along the wire.
so we have the formulae
\frac{d \frac{\delta T}{\delta r}}{dt} - \frac{\delta T}{\delta r}=Q
where Q is the generalized force acting on the object ...
goldstein claims that is 0 here i don't get that how?
 
Physics news on Phys.org
First, correcting the typos, Lagrange's equation is

\frac{d}{dt} \frac{\partial L}{\partial \dot{r}} - \frac{\partial L}{\partial r}=Q

There is no potential so L=T in this example as you have stated. In the method described on p. 26, the generalized force Q is zero because the constraint of moving along the wire is built into the generalized coordinates instead, and there are no non-conservative forces (i.e., friction).
 
Thread 'Gauss' law seems to imply instantaneous electric field propagation'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Thread 'A scenario of non-uniform circular motion'
(All the needed diagrams are posted below) My friend came up with the following scenario. Imagine a fixed point and a perfectly rigid rod of a certain length extending radially outwards from this fixed point(it is attached to the fixed point). To the free end of the fixed rod, an object is present and it is capable of changing it's speed(by thruster say or any convenient method. And ignore any resistance). It starts with a certain speed but say it's speed continuously increases as it goes...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
Back
Top