
#1
Sep708, 08:36 PM

P: 13

1. The problem statement, all variables and given/known data
22. The average person passes out an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time would be required for the car to accelerate from rest to 60.0 miles per hour? (The car would need rocket boosters!) 2. Relevant equations 3. The attempt at a solution v1 = 60 v0 = 0 a = 7 * 9.8 => 68.6m/s^2 a = change in velocity/change in time So, 68.6m/s^2 = 60mph/t 68.6 * t = 60mpg t = 60/68.6 = 0.87 seconds I am not sure if this is correct or not. The answer seems within reason since a very high powered sports car accelerates from 060 miles per hour in around 3 seconds, so 0.87 seconds would line up well with the exaggeration of the speed of the car mentioned at the end of the word problem. Any help is appreciated :). 



#2
Sep708, 09:22 PM

P: 117

You are mixing English and SI units.




#3
Sep708, 09:38 PM

P: 13





#4
Sep708, 09:46 PM

P: 180

Acceleration, Solve for time (Algebra Based)
Dig.
What he/she meant was that you are using G's (or 9.8m/s^{2}) which is the acceleration on earth in metric, and then Miles per hour, which is SI. To fix this, take the MPH and multiply by .44 (or to be more exact, .44704) to get meters/second By the way, the way to get the .44 is roughly 1600 meters/3600seconds = .44 (mile/hour hour=60 minutes=60 seconds. so 60[SUP]2[SUP]) This should give you some help, or at least point you in the correct direction. Your equation is correct though. 



#5
Sep708, 10:09 PM

P: 13

I see my mistake now. Thank you both for pointing that out to me. 



#6
Sep708, 10:35 PM

P: 180

No problem Dig,
That seems correct to me. Good luck in physics this year. 



#7
Sep708, 10:36 PM

P: 13




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