Finding Speed and Direction of Relative Motion on a Moving Ship

  • Thread starter Thread starter undrcvrbro
  • Start date Start date
  • Tags Tags
    Vector
undrcvrbro
Messages
131
Reaction score
0

Homework Statement


A child walks due east on the deck of a ship at 1 miles per hour.
The ship is moving north at a speed of 4 miles per hour.

Find the speed and direction of the child relative to the surface of the water.


Homework Equations





The Attempt at a Solution


I've already found the magnitude. But now I can't find the direction.

They want:

"The angle of the direction from the north = "

What does that mean? I've solved it using the inverse tangent for both angles of the triangle and apparently neither is right. So maybe it's even simpler than I think?
 
Physics news on Phys.org
undrcvrbro said:

Homework Statement


A child walks due east on the deck of a ship at 1 miles per hour.
The ship is moving north at a speed of 4 miles per hour.

Find the speed and direction of the child relative to the surface of the water.


Homework Equations





The Attempt at a Solution


I've already found the magnitude. But now I can't find the direction.

They want:

"The angle of the direction from the north = "

What does that mean? I've solved it using the inverse tangent for both angles of the triangle and apparently neither is right. So maybe it's even simpler than I think?
What did you get for the angle relative to north? It should be somewhere between 10 and 20 degrees east of north.
 
Mark44 said:
What did you get for the angle relative to north? It should be somewhere between 10 and 20 degrees east of north.
I got 14.03624347...in radians .2449786631(exact enough for you?:-p)...does that sound about right?
 
undrcvrbro said:
I got 14.03624347...in radians .2449786631(exact enough for you?:-p)...does that sound about right?

Your first value agrees with mine. I didn't calculate it in radians.
 
Mark44 said:
Your first value agrees with mine. I didn't calculate it in radians.
Okay, cool. Thanks Mark, for all the help this morning(it's 2:30 here in Ohio). I can now begin my Materials and Energy Balances homework!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top