# Logic Networks/Seven Segment Displays

by Fr33t
Tags: displays, logic, networks or seven, segment
 P: 2 1. The problem statement, all variables and given/known data Here's the problem: Design a logic network that can display the characters in “APPLE” on a sevensegment display unit. Write the truth table for the output functions C0-C6, minimize them by using Karnaugh Map, and implement using discrete logic gates. (Hints: Character “A” will be displayed if segments (C0, C1, C2, C4, C5, C6) of a 7- segment display are turned on and segment (C3) is turned off. Since only 4 characters will be displayed, input of 2 bits to encode them will be needed for the given design.) Now, where I get confused is when it says an input of 2 bits to encode them will be needed. I understand that technically only 2 bits are needed, but I do not understand how to implement it using only 2 instead of 4. I've been searching and thinking of different ways to do it but I am stumped. 2. Relevant equations Not quite applicable 3. The attempt at a solution With 2 bits to work with: 00 = A 01 = P 10 = L 11 = E A B C0 C1 C2 C3 C4 C5 C6 0 0 1 1 1 0 1 1 1 0 1 1 1 0 0 1 1 1 1 0 0 0 0 1 1 1 0 1 1 1 0 0 1 1 1 1 But what is the point of using a K Map for this? I am almost sure this is where I am wrong but I have no idea what to do? Any help will be greatly appreciated! Thanks Attached Thumbnails
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P: 37,649
 Quote by Fr33t 1. The problem statement, all variables and given/known data Here's the problem: Design a logic network that can display the characters in “APPLE” on a sevensegment display unit. Write the truth table for the output functions C0-C6, minimize them by using Karnaugh Map, and implement using discrete logic gates. (Hints: Character “A” will be displayed if segments (C0, C1, C2, C4, C5, C6) of a 7- segment display are turned on and segment (C3) is turned off. Since only 4 characters will be displayed, input of 2 bits to encode them will be needed for the given design.) Now, where I get confused is when it says an input of 2 bits to encode them will be needed. I understand that technically only 2 bits are needed, but I do not understand how to implement it using only 2 instead of 4. I've been searching and thinking of different ways to do it but I am stumped. 2. Relevant equations Not quite applicable 3. The attempt at a solution With 2 bits to work with: 00 = A 01 = P 10 = L 11 = E A B C0 C1 C2 C3 C4 C5 C6 0 0 1 1 1 0 1 1 1 0 1 1 1 0 0 1 1 1 1 0 0 0 0 1 1 1 0 1 1 1 0 0 1 1 1 1 But what is the point of using a K Map for this? I am almost sure this is where I am wrong but I have no idea what to do? Any help will be greatly appreciated! Thanks
Welcome to the PF.

Everything you've done looks correct. Now just do the 7 K-maps (or just write the 7 equations) that define the logic that drives the 7-segment displays. The same logic is repeated at each display, and drives the 7 segments based on that 2-bit input AB.

BTW, I edited your post to insert Code tags around your table. This preserves the column alignment.
 P: 2 Thanks a million berkeman, I think I got it all figured out!

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