What Causes Data Signal Attenuation Over Different Cable Lengths?

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Discussion Overview

The discussion revolves around the causes of data signal attenuation over different cable lengths, specifically comparing 500-foot and 5000-foot cables. Participants explore theoretical and practical aspects of signal transmission, including factors influencing attenuation in network cables.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant requests a general formula or explanation for signal attenuation differences over varying cable lengths.
  • Another participant notes that there is no simple formula due to the influence of transmitter and receiver impedances, as well as the wire's impedance.
  • A different participant explains that practical transmission lines are affected by the non-ideal behavior of inductors and capacitors, emphasizing the importance of construction details and material properties.
  • One suggestion is made to consult manufacturers of digital cables and signal equipment for specific solutions and calculations.
  • A participant reiterates the need for a book on transmission lines, indicating the complexity of the topic.
  • Another participant clarifies their intent to discuss the topic in general terms, assuming ideal conditions without power loss at the source or receiver.
  • Areas of Agreement / Disagreement

    Participants generally agree on the complexity of the topic and the need for further resources, but there is no consensus on a simple formula or explanation for the differences in attenuation.

    Contextual Notes

    The discussion highlights limitations in providing a straightforward answer due to the dependence on various factors such as impedance and material properties, which are not fully resolved in the conversation.

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Can anyone give me a good general formula or expanation for the diference in attenuation in a data signal in a network over a 500 and a 5000 foot cable?
Help would be much appreciated. Thanx!
 
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There is no simple formula, since the result depends highly on both the transmitter and receiver impedances, as well as the impedance of the wire.

You might want to consider finding a book on transmission line theory in your local university library.

- Warren
 
A general explanation is that there is no such thing as a perfect inductor or capacitor. There is always some combination of L+R+C going on. While two of those components may be very small they are not necessarily negligible.
Attenuation in a practical transmission line is dependent on construction details, manufacturing tolerance and material properties.

If you are interested in practical transmission lines then the ARRL Handbook might be a good choice.
 
if you have a specific requirement in mind. solutions are but a phone call away. don't reinvent the wheel. call manufacturers of digital cable and, digital signal equipment. they will give you all the information you need.free of charge, they will provide you with calculations, and solutions. it is a special and gifted person who thinks beyond those that design, market, and sell a required commodity!
 
I am trying to be as general as posible. Assuming the two wires are the same, and there is no power lost at the source or at the reciever. Just a basic data stream that travels from point A to point B.
Again, Thank you for help.
 
I think we've already answered your question then -- you need a book on transmission lines. This topic is not simple.

- Warren
 

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