# Derivation of the Equilibrium Constant

by gsingh2011
Tags: constant, derivation, equilibrium
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 P: 113 I'm trying to understand this: http://en.wikipedia.org/wiki/Equilib...bs_Free_Energy And there are few steps that I don't get. My first question is probably a stupid one, but where does the $$\Sigma$$v$$_{j}$$A$$_{j}$$=0 come from? What exactly is it summing up, the number of atoms? Are you assuming that the products side is negative? (Because I don't see how else you would get zero) And why does it only go up to n? I'll ask my other questions after I get some replies because it's possible I'll figure them out after I read the replies.
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P: 23,714
 Quote by gsingh2011 where does the $$\Sigma$$v$$_{j}$$A$$_{j}$$=0 come from? What exactly is it summing up, the number of atoms? Are you assuming that the products side is negative? (Because I don't see how else you would get zero) And why does it only go up to n?
My guess is it is just a mass conservation, and yes, products are negative.
P: 113
 Quote by Borek My guess is it is just a mass conservation, and yes, products are negative.
Ok, but why does it only sum up to n? The first equation in the derivation shows the first product being n but then shows more products after that. If it was mass conservation, wouldn't it have to sum passed n?

 Admin P: 23,714 Derivation of the Equilibrium Constant Where does it sum only to n? It sums for all j.

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