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∫(4dx)/sqrt(4x  x^2)by notSomebody
Tags: dx or sqrt4x 
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#1
Feb612, 09:11 PM

P: 5

1. The problem statement, all variables and given/known data
[itex]∫\frac{4dx}{\sqrt{4x  x^2}}[/itex] 2. Relevant equations [itex]arcsin(\frac{x}{a}) = \frac{1}{\sqrt{a^2X^2}}[/itex] Correct Answer: 4sin^{1}[itex]\frac{1}{2}[/itex](x + 2) + c 3. The attempt at a solution I am completely lost with this one. I tried pulling a [itex]\sqrt{x}[/itex] out of the bottom. [itex]∫\frac{4dx}{\sqrt{x}\sqrt{4  x}}[/itex] u = [itex]\sqrt{x}[/itex] du = [itex]\frac{1}{2}x^{1/2}dx[/itex] [itex]8∫\frac{du}{\sqrt{4u^2}}[/itex] So [itex]a^2 = 4[/itex] [itex]\sqrt{4}[/itex] is not a real number. I would appreciate any help you could give. Thanks. 


#2
Feb612, 09:32 PM

P: 312

try4x4x^2=4(x+2)^2



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