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MOMENTUM, contact time, need help 
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#1
Mar1305, 03:13 PM

P: 7

A 50g golf ball is struck w a club. the ball leaves the face of the club w a velocity of 44m/s
Pf = mvf = (50 x 10^3 kg) (44 m/s) = 2.2 kg m/s From this I must find the contact time t = change in x /average velocity The change in x in the radius of the ball .05m The average velocity provided in the solution is 22 m/s I do not understand how this figure of 22 m/s was obtained from the original velocity of 44 m/s Help anyone 


#2
Mar1305, 04:06 PM

P: 787

Where did you get the change in x is .05 m? That information wasn't given to you in the problem... is



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