MOMENTUM, contact time, need help

mushhhy

A 50g golf ball is struck w a club. the ball leaves the face of the club w a velocity of 44m/s

Pf = mvf = (50 x 10^-3 kg) (44 m/s) = 2.2 kg m/s

From this I must find the contact time t = change in x /average velocity

The change in x in the radius of the ball .05m

The average velocity provided in the solution is 22 m/s

I do not understand how this figure of 22 m/s was obtained from the original velocity of 44 m/s

Help anyone

Jameson

Where did you get the change in x is .05 m? That information wasn't given to you in the problem... is all you were given?