Register to reply

MOMENTUM, contact time, need help

by mushhhy
Tags: contact, momentum, time
Share this thread:
mushhhy
#1
Mar13-05, 03:13 PM
P: 7
A 50g golf ball is struck w a club. the ball leaves the face of the club w a velocity of 44m/s

Pf = mvf = (50 x 10^-3 kg) (44 m/s) = 2.2 kg m/s

From this I must find the contact time t = change in x /average velocity

The change in x in the radius of the ball .05m

The average velocity provided in the solution is 22 m/s

I do not understand how this figure of 22 m/s was obtained from the original velocity of 44 m/s

Help anyone
Phys.Org News Partner Science news on Phys.org
Hoverbike drone project for air transport takes off
Earlier Stone Age artifacts found in Northern Cape of South Africa
Study reveals new characteristics of complex oxide surfaces
Jameson
#2
Mar13-05, 04:06 PM
P: 788
Where did you get the change in x is .05 m? That information wasn't given to you in the problem... is
A 50g golf ball is struck w a club. the ball leaves the face of the club w a velocity of 44m/s
all you were given?


Register to reply

Related Discussions
Momentum in the time direction Special & General Relativity 4
Time Dilation - Angular Momentum - Mass Special & General Relativity 1
Foot contact time. General Physics 4
Estimating contact-time Advanced Physics Homework 8