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MOMENTUM, contact time, need help

by mushhhy
Tags: contact, momentum, time
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mushhhy
#1
Mar13-05, 03:13 PM
P: 7
A 50g golf ball is struck w a club. the ball leaves the face of the club w a velocity of 44m/s

Pf = mvf = (50 x 10^-3 kg) (44 m/s) = 2.2 kg m/s

From this I must find the contact time t = change in x /average velocity

The change in x in the radius of the ball .05m

The average velocity provided in the solution is 22 m/s

I do not understand how this figure of 22 m/s was obtained from the original velocity of 44 m/s

Help anyone
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Jameson
#2
Mar13-05, 04:06 PM
P: 787
Where did you get the change in x is .05 m? That information wasn't given to you in the problem... is
A 50g golf ball is struck w a club. the ball leaves the face of the club w a velocity of 44m/s
all you were given?


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