Quick question regarding speed & constant acceleration

by NutriGrainKiller
Tags: acceleration, constant, speed
 P: 1,236 Ok so for this type of problem you have to use your kinematic equations. We are given a distance between two points, the time it takes for the antelope to cover that distance, and the speed when it passes the second point. So we need to use an equation that contains all these variables. We would use $x = x_{0} + \frac{1}{2}(v_{x}_{0}+v_{x})t$. We could rewrite this as $x - x_{0} = \frac{1}{2}(v_{x}_{0}+v_{x})t$. $x - x_{0}$ is really the distance, so $75 = \frac{1}{2}(v_{x}_{0} + 14)(7.60)$. So just solve for $v_{x}$. For the second question, use the equation $x - x_{0} = v_{x}_{0}t + \frac{1}{2}a_{x}t^{2}$. $x_{0} = 0$ and you know $v_{x}_{0}$ and $t$ from the previous question. So just solve for $a$.
 Quote by courtrigrad Ok so for this type of problem you have to use your kinematic equations. We are given a distance between two points, the time it takes for the antelope to cover that distance, and the speed when it passes the second point. So we need to use an equation that contains all these variables. We would use $x = x_{0} + \frac{1}{2}(v_{x}_{0}+v_{x})t$. We could rewrite this as $x - x_{0} = \frac{1}{2}(v_{x}_{0}+v_{x})t$. $x - x_{0}$ is really the distance, so $75 = \frac{1}{2}(v_{x}_{0} + 14)(7.60)$. So just solve for $v_{x}$. For the second question, use the equation $x - x_{0} = v_{x}_{0}t + \frac{1}{2}a_{x}t^{2}$. $x_{0} = 0$ and you know $v_{x}_{0}$ and $t$ from the previous question. So just solve for $a$.