Undetermined Coefficients / Variation of Parameters

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SUMMARY

The discussion centers on solving the ordinary differential equation (ODE) y'' + 4y = 4sec(2t) using the method of undetermined coefficients. The user attempted a particular solution of the form Yp = Acos(2t) + Bsin(2t), which was unsuccessful. It was concluded that the method of undetermined coefficients is not applicable in this case because the right-hand side, 4sec(2t), does not correspond to a particular solution of any homogeneous linear differential equation with constant coefficients.

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  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with the method of undetermined coefficients
  • Knowledge of variation of parameters
  • Concept of homogeneous linear differential equations with constant coefficients
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amcavoy
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I know how to solve the following ODE with variation of parameters:

[tex]y''+4y=4\sec{\left(2t\right)}.[/tex]

Is there any way to solve this with undetermined coefficients? So far I have tried Yp=Acos(2t)+Bsin(2t), but that didn't work.

Thanks for the help.
 
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Now that I try different methods, it seems that reduction of order won't work. At least, I come up with a function I can't integrate:

Y=vyh

v'=u

[tex]u=\frac{2c_1t-2c_2\ln{\left(\cos{2t}\right)}}{c_1\cos{2t}+c_2\sin{2t}}[/tex]
 
apmcavoy said:
I know how to solve the following ODE with variation of parameters:
[tex]y''+4y=4\sec{\left(2t\right)}.[/tex]
Is there any way to solve this with undetermined coefficients? So far I have tried Yp=Acos(2t)+Bsin(2t), but that didn't work.
Thanks for the help.

The method of undetermined coefficients is applicable only if the RHS of the non-homogeneous equation is itself a particular solution of some homogeneous linear differential equation with constant coefficients. Since Sec(2t) is not such a solution, this method is not applicable.
 

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