Please explain your reasoning behind this equation.Jeff Nilsson said:ΣF = 9.8(1.05m + m)
haruspex said:Please explain your reasoning behind this equation.
What forces act on the person during the acceleration?
What acceleration results?
Maybe I misunderstand your notation, but that appears to reduce to 9.8(2.05)m. Is that what you meant?Jeff Nilsson said:the 9.8(1.05m+m) part is to find the force acting on the person when the elevator starts accelerating upward
It will. When you have corrected your "9.8(1.05m+m)" and written it in simplest form, equate it to "ma", as in ΣF=ma.Jeff Nilsson said:nothing cancels
To calculate elevator acceleration, you need to apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula for calculating acceleration is a = F/m, where "a" is the acceleration, "F" is the net force, and "m" is the mass of the elevator.
The formula for solving for F=ma is F = m * a, where "F" is the net force, "m" is the mass, and "a" is the acceleration. This formula is derived from Newton's second law of motion, which relates force, mass, and acceleration.
To determine the mass of the elevator, you can use a scale to measure the weight of the elevator. Then, use the formula F = m * g, where "F" is the weight, "m" is the mass, and "g" is the acceleration due to gravity (9.8 m/s^2). Rearrange the formula to solve for "m" and you will have the mass of the elevator.
The units for acceleration when solving for F=ma should be meters per second squared (m/s^2). This is the standard unit of measurement for acceleration in the metric system.
Yes, this formula can be used to calculate acceleration for any elevator as long as the net force and mass are known. It is important to note that the formula assumes the elevator is moving in a straight line and at a constant speed.