Calculus and Vectors - Determining Vector and Parametric Equations

In summary, to determine vector and parametric equations for a plane containing the point A(2, 3, -1) and parallel to the plane with equation (x, y, z) = (2, 1, -3) + s(5, 2, -1) + t(3, -2, 4), we can add A as a vector to all the points of the given plane to obtain the equation (x, y, z) = A + s(5, 2, -1) + t(3, -2, 4). This equation will contain the same two vectors as the given plane and will pass through the point A(2, 3, -1
  • #1
ttpp1124
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4
Homework Statement
Determine vector and parametric equations for the plane containing the point A(2, 3, -1) and parallel to the plane with equation (x, y, z) = (2, 1, -3) + s(5, 2, -1) + t(3, -2, 4).

Can someone confirm?
Relevant Equations
n/a
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  • #2
ttpp1124 said:
Homework Statement:: Determine vector and parametric equations for the plane containing the point A(2, 3, -1) and parallel to the plane with equation (x, y, z) = (2, 1, -3) + s(5, 2, -1) + t(3, -2, 4).

Can someone confirm?
Relevant Equations:: n/a

View attachment 260205
Comment: Your vector equation isn't an equation. An equation always has '=' in it.
Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.
 
  • #3
Mark44 said:
Comment: Your vector equation isn't an equation. An equation always has '=' in it.
Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.

To obtain a plane parallel to P0 and passing through the point A(2,3,−1), all we need to do is add A as a vector (I dropped the coordinates for brevity) to all the points of P0. This gives us the plane

(𝑥,𝑦,𝑧)=𝐴+𝑠(5,2,−1)+𝑡(3,−2,4)
 
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  • #4
ttpp1124 said:
To obtain a plane parallel to P0 and passing through the point A(2,3,−1), all we need to do is add A as a vector (I dropped the coordinates for brevity) to all the points of P0. This gives us the plane

(𝑥,𝑦,𝑧)=𝐴+𝑠(5,2,−1)+𝑡(3,−2,4)
Yes,, I understand how you got the equation, but I was responding to your request for someone to verify that your work was correct. Here's what I said before:
Mark44 said:
Can you check these for yourself? Does your plane contain the point A(2, 3, -1)? Since your plane is parallel to the given plane, it should contain the same two vectors as the given plane.
One of the things I've always liked about mathematics, especially at somewhat higher levels, is that it's not difficult to verify your work for yourself. What I said above was how you can do this.
 

1. What is the difference between a vector and a parametric equation?

A vector is a mathematical object that represents a magnitude and direction, while a parametric equation is a set of equations that describe the relationship between two or more variables. In the context of calculus and vectors, a vector equation is often used to represent a line or curve in space, while a parametric equation is used to describe the coordinates of points along that line or curve.

2. How do you determine the vector equation of a line in three-dimensional space?

To determine the vector equation of a line in three-dimensional space, you need to know a point on the line and the direction vector of the line. The vector equation can then be written as r = a + tb, where r is the position vector of any point on the line, a is the known point, t is a scalar parameter, and b is the direction vector.

3. What is the process for finding the parametric equations of a curve?

To find the parametric equations of a curve, you first need to express the curve in vector form. This can be done by writing the curve as the sum of two or more vectors. Then, each component of the vectors can be expressed as a function of a parameter, typically denoted by t. These functions will form the parametric equations of the curve.

4. Can you use calculus to find the vector and parametric equations of a curve?

Yes, calculus can be used to find the vector and parametric equations of a curve. Calculus concepts such as derivatives and integrals can be applied to vector equations to find the slope, curvature, and other properties of the curve. These properties can then be used to determine the parametric equations of the curve.

5. How do you convert between vector and parametric equations?

To convert between vector and parametric equations, you can use the components of the vector equation to form the parametric equations. The coordinates of the points on the curve can then be expressed as functions of a parameter, which will form the parametric equations. Conversely, the parametric equations can be combined to form the vector equation by expressing each coordinate as a function of the parameter and then combining them into a single vector equation.

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