Cartesian to Cylindrical coordinates?

In summary, you input the equations z = -i*x + j*y + k*z into R and get:R = -ix+iy+zkThis equation can be rewritten asR = xi+yi+zkThis equation can be rewritten asR = i+j+k
  • #1
shreddinglicks
212
6

Homework Statement


I want to convert R = xi + yj + zk into cylindrical coordinates and get the acceleration in cylindrical coordinates.

Homework Equations


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z

The Attempt at a Solution


I input the equations listed into R giving me:

R =
Inline33.gif
i +
Inline36.gif
j + z k

Apply chain rule twice:

Inline209.gif


The final answer is:

Inline212.gif


How do I get this final answer? It looks like the terms with sin were dropped. How does this happen?
 

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  • #2
Your result is an expression for the acceleration using the Cartesian vector basis (i.e., you are showing the Cartesian components expressed in terms of the cylinder coordinates). You need to relate this to the vector components using the cylinder coordinate basis vectors.
 
  • #3
Orodruin said:
Your result is an expression for the acceleration using the Cartesian vector basis (i.e., you are showing the Cartesian components expressed in terms of the cylinder coordinates). You need to relate this to the vector components using the cylinder coordinate basis vectors.

I don't think I understand. By basis you mean the unit vectors in rHat, thetaHat, zHat?
 
  • #4
Yes, that is the basis that you should be using to express your vector as done in the quoted result.
 
  • #5
Orodruin said:
Yes, that is the basis that you should be using to express your vector as done in the quoted result.

So I have:

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I don't see how I replace i,j,k with these to get the answer.
 

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  • #6
You have a result for your vector. You need to express it as a linear combination of the vector basis, i.e., you need to find ##v_r##, ##v_\theta## and ##v_z## such that
$$
\vec v = v_r \hat r + v_\theta \hat \theta + v_z \hat z.
$$
Since you have three components, this is a system of three equations for three unknowns.
 
  • #7
Orodruin said:
You have a result for your vector. You need to express it as a linear combination of the vector basis, i.e., you need to find ##v_r##, ##v_\theta## and ##v_z## such that
$$
\vec v = v_r \hat r + v_\theta \hat \theta + v_z \hat z.
$$
Since you have three components, this is a system of three equations for three unknowns.
I see it. Thanks!
 

1. What are Cartesian coordinates?

Cartesian coordinates are a system used to describe the position of a point in space using three perpendicular axes - the x-axis, y-axis, and z-axis. The point is represented by three numbers (x,y,z) that indicate its distance from each axis.

2. What are cylindrical coordinates?

Cylindrical coordinates are an alternative system used to describe the position of a point in space. It uses two perpendicular axes - the radial distance from the origin and the angle of rotation around the z-axis, along with the z-coordinate to determine the position of a point.

3. How do you convert from Cartesian to cylindrical coordinates?

To convert from Cartesian to cylindrical coordinates, you can use the following formulas:

r = √(x² + y²)

θ = tan⁻¹(y/x)

z = z

4. What are the advantages of using cylindrical coordinates?

One advantage of using cylindrical coordinates is that it is often easier to work with in certain situations, such as when dealing with objects with cylindrical symmetry. It can also simplify calculations in some cases, making it a useful tool in mathematics and physics.

5. Can you convert from cylindrical to Cartesian coordinates?

Yes, it is possible to convert from cylindrical to Cartesian coordinates using the following formulas:

x = rcosθ

y = rsinθ

z = z

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