You're first asked about the "full energy" of the of the comet's orbit. Presumably that's the mechanical energy. What is the expression for the specific mechanical energy (ξ) of an orbit? What is its value for any parabolic orbit?math 2015 said:
Okay, now you'll have to show some details of your efforts so far to answer the given problem.math 2015 said:
A parabolic orbit is a type of trajectory that is followed by an object as it moves around a central body, such as the Sun. It is characterized by a shape that resembles a stretched out letter 'U' and is often described as being halfway between a circular and a hyperbolic orbit.
A comet follows a parabolic orbit around the Sun when it is traveling at a high enough velocity to escape the gravitational pull of the Sun, but not enough to leave the solar system completely. This allows the comet to continuously loop around the Sun in a parabolic path.
The shape and size of a comet's parabolic orbit is determined by its initial velocity and the gravitational pull of the Sun. Comets with higher initial velocities will have larger and more elongated orbits, while those with lower velocities will have smaller and more circular orbits.
The time it takes for a comet to complete a parabolic orbit around the Sun can vary depending on its distance from the Sun and its velocity. On average, it can take anywhere from a few years to a few decades for a comet to complete one full orbit.
If a comet gets too close to the Sun, it can be affected by its immense gravitational pull. This can cause the comet's orbit to become more elliptical or even change to a hyperbolic orbit, which would result in the comet leaving the solar system entirely.