Comparing Carnot & Ranking Cycles + Steady Flow Energy Equation

[therichman]

Please i need answer for this questions

A- compare the Carnot cycle with the Ranking Cycle
B- State The Steady Flow Energy equation and discuss the Origin and definition of each of the terms
c- A vapour compression refrigeration using ammonia works at a condenser temperature of 40C and an evaporator temperature of -5C the refrigerant leaves the evaporator as a saturated vapour.
calculate the refigerations effect and coefficient of performance if
a) the refrigerant leaves the condenser saturated
b) the refrigerant is subcooled to 20 C before entering the throttle valve

thanks

 

[Navin A S]

A- The Carnot cycle is a theoretical reversible cycle in which a heat engine operates between two temperatures, while the Rankine cycle is an idealized thermodynamic cycle that converts heat into work. The Carnot cycle consists of two isothermal processes and two adiabatic processes, whereas the Rankine cycle consists of one isothermal process, two constant-pressure processes, and one constant-volume process. Both cycles are thermodynamically efficient, but the Carnot cycle is more efficient than the Rankine cycle due to its higher Carnot efficiency.B- The Steady Flow Energy equation is a statement of the conservation of energy applied to systems with a single inlet and a single outlet. It states that the sum of the kinetic energy, potential energy and internal energy at any point in a system is equal to the sum of these energies at any other point in the system. The origin of this equation can be traced back to the first law of thermodynamics, which states that energy can neither be created nor destroyed, only transferred or converted from one form to another. The terms in the equation represent the various forms of energy present in the system, including kinetic energy (KE), potential energy (PE), and internal energy (IE). C- a) Refrigeration effect = 40 - (-5) = 45 K Coefficient of Performance = 45 / 40 = 1.125 b) Refrigeration effect = 40 - 20 = 20 K Coefficient of Performance = 20 / 40 = 0.5