Convection between two plates

In summary, the conversation revolves around equations for convection between two plates and how the navier-stokes equation is used to derive them. There is a discrepancy between equations 9.5 from the lecture notes and the equation from Tritton's book, which is explained by the pressure term in the equations taking into account the contribution of other forces such as gravity. The conversation concludes with the understanding that the lecture notes did not specify the derivation, but the discrepancy is resolved by accounting for the derivative of ρ0g being zero in the horizontal direction.
  • #1
unscientific
1,734
13

Homework Statement



From my lecture notes, here are the equations for convection between two plates. I have derived equations 9.6, 9.7 and 9.8. But for 9.4 there's a problem when gravity becomes involved.

rcltuh.png


Homework Equations



Navier stokes: ## \rho \frac{D \vec u}{D t} = -\nabla p + \mu \nabla^2 \vec u + \vec F ##

The Attempt at a Solution


[/B]
However, I was reading through Tritton's book on flows where he detailed the derivation:

Starting from the navier-stokes equation:

[tex]\rho \frac{D \vec u}{D t} = -\nabla p + \mu \nabla^2 \vec u + \vec F [/tex]

where ##\vec F## represents contribution of other forces (such as gravity).

They then begin to define ##\vec F##:

By letting density vary, we have ##\rho = \rho_0 + \Delta \rho##. Gravitational acceleration can be defined through a potential: ##\vec g = -\nabla \phi = -\nabla gz##. Thus,

[tex]\vec F = -(\rho_0 + \Delta \rho)\nabla \phi = -\nabla(\rho_0 \phi) + \Delta \rho \vec g[/tex]

Introducing ##P = p + \rho_0 \phi##, navier stokes becomes:

[tex] \rho_0 \frac{D\vec u}{D t} = -\nabla P + \mu \nabla^2 \vec u + \Delta \rho \vec g [/tex]
 
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  • #2
You haven't told us what your problem is.

Chet
 
  • #3
Chestermiller said:
You haven't told us what your problem is.

Chet

Equations 9.5 from the lecture notes and eqn from the book doesn't match
 
  • #4
unscientific said:
Equations 9.5 from the lecture notes and eqn from the book doesn't match
What it is about them that you feel doesn't match?

Chet
 
  • #5
Chestermiller said:
What it is about them that you feel doesn't match?

Chet

Substituting ##P## inside and changing ##\nabla## to ##\frac{\partial}{\partial z}##, it gives:

[tex]\rho_0 \frac{D\vec u}{D t} = -\nabla P + \mu \nabla^2 \vec u + \Delta \rho \vec g[/tex]
[tex]\rho_0 \frac{D\vec u}{D t} = - \frac{\partial}{\partial z}(p + rho_0 \phi) + \mu \nabla^2 \vec u + \Delta \rho \vec g [/tex]
[tex]\rho_0 \frac{D\vec u}{D t} = - \frac{\partial}{\partial z}(p - rho_0 z \vec g) + \mu \nabla^2 \vec u + \Delta \rho \vec g [/tex]
[tex]\rho_0 \frac{D\vec u}{D t} = - \frac{\partial p}{\partial z} + \rho_0 \vec g + \mu \nabla^2 \vec u + (\rho - \rho_0) \vec g [/tex]
[tex]\rho_0 \frac{D\vec u}{D t} = - \frac{\partial p}{\partial z} + \mu \nabla^2 \vec u + \rho \vec g [/tex]
[tex]\frac{D\vec u}{D t} = - \frac{1}{\rho_0} \frac{\partial p}{\partial z} + \frac{1}{\rho_0}\mu \nabla^2 \vec u + \frac{\rho}{\rho_0} \vec g [/tex]
 
  • #6
It appears that the p's in Eqns. 9 are what you are calling P. The ρ0g has apparently been absorbed into the pressure term.

Chet
 
  • #7
Chestermiller said:
It appears that the p's in Eqns. 9 are what you are calling P. The ρ0g has apparently been absorbed into the pressure term.

Chet

I don't think that's right, as applying the same equation in the horizontal direction (w) gives eqn 9.4. The small ##p## in eqn 9.4 should not include ##\rho_0\phi##.
 
  • #8
unscientific said:
I don't think that's right, as applying the same equation in the horizontal direction (w) gives eqn 9.4. The small ##p## in eqn 9.4 should not include ##\rho_0\phi##.
The derivative of ##\rho_0g## is zero in the horizontal direction.
 
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Likes unscientific
  • #9
Chestermiller said:
The derivative of ##\rho_0g## is zero in the horizontal direction.

Ah that's true. Quite annoying when the lecture notes don't specify the derivation, but this makes sense! Thanks alot.
 
  • #10
Got the answer, thanks alot!
 
Last edited:

What is convection between two plates?

Convection between two plates refers to the transfer of heat through the movement of fluids (such as air or water) between two surfaces or plates that have different temperatures.

How does convection between two plates occur?

Convection between two plates occurs when the warmer fluid near one plate rises and the cooler fluid near the other plate sinks. This creates a circular motion of fluids, which allows for heat to be transferred between the two plates.

What factors affect convection between two plates?

The main factors that affect convection between two plates are the temperature difference between the two plates, the type of fluid involved, and the distance between the plates. Other factors such as the surface roughness of the plates and the presence of obstacles can also influence convection.

What are the applications of convection between two plates?

Convection between two plates has various applications in our daily lives, such as in cooking, heating and cooling systems, and weather patterns. It is also an important process in geology, contributing to plate tectonics and the movement of Earth's crust.

How is convection between two plates related to climate change?

Convection between two plates plays a role in climate change by influencing ocean currents and atmospheric circulation patterns, which in turn impact global climate. Changes in plate movement can also affect the distribution of land masses and alter climate patterns over long periods of time.

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