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Deimantas
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Homework Statement
From a height of 18 meters above ground, an object is thrown vertically upwards at a speed of 30m/s. Find the equation where height h depends on time t. Find the maximum height of the object.
Homework Equations
h=h0+v0t-(gt^2)/2
The Attempt at a Solution
The equation of motion of an object thrown vertically upwards is h=h0+v0t-(gt^2)/2
By inserting h0=18 and v0=30 we get
[itex]h=18+30t-(gt^2)/2[/itex], which is the correct answer. When t=3, h is max at 63.
Now my problem here is that instead of finding the aforementioned equation of motion in a book, i was supposed to create it myself, using differential equation methods. How?
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